Question

4 massed having values as shown are kept at the 4 corners of a square of side a the resultant gravitational field at the centre of the square is along the direction

Answer 1

Potential energy of the system is given by:U = −GM2a+−GM2a+−GM2a+−GM2a2√+−GM2a2√+−GM2aU = −2GM2a(2+12√)gravitational potential of the system = U/m =−2GMa(2+12√)