Question

4 men & 6 boys can finish a work in 5 days while 3 men & 4 boys can finish it in 7 days . Find the time taken by 1 man & 1 boy alone?

Answer 1

hope this helps you☺☺☺☺

Answer 2

Thus so

_____________________________________________________________

. SO HERE WE GO ⤵


. THEN

. ONE MAN S ONE DAY WORK = 1 / X

. ONE BOY S ONE DAY WORK = 1 / Y

. SO

. FOUR MEN S ONE DAY S WORK = 4 / X

SIX BOY S ONE DAY S WORK = 6 / Y

AS 4 MEN AND 6 BOY S CAN FINISH THE WORK IN 5 DAY S

➡ 5 { 4 / X + 6 / Y } = 1

. 20 / X + 30 / Y = 1 ___@


AGAIN AS

. 3 MEN 4 BOY S CAN FINISH THE WORK IN 7 DAY S

. ➡ 7 { 3 / X + 4 / Y } = 1

. 21 / X + 28 / Y = 1 ____₹


. SO LET 1 / X = A

. 1 / Y = B


. BY MULTIPLYING @ BY 21 AND ₹ BY 20


. WE GET

. 420 A + 630 B = 21 ___@

. 420 A + 560 B = 20 ____₹


BY SUBTRACTING ₹ FROM @

. 70 B = 1

. B = 1 / 70


. THEN
. B IN @

. 20 A + 30 ( 1 / 70 ) = 1

. 140 A = 7 - 3

. A = 4 / 140

. A = 1 / 35


. THEN

. 1 / X = 1 / 35

. X = 35

. 1 / Y = 1 / 70

. Y = 70

. SO

. 1 MEN CAN FINISH IN 35 DAY S

. 1 BOY CAN FINISH IN 70 DAY S


. Hope it helps


. @g. :( *ana* :)