4 men and 4 women can build a room in 5 days. 7 men and 2 women will take 4 days to complete the same piece of work. How many days will 6 men and 1 woman take to complete twice the job?
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The number of days taken by 6 men and 1 woman to complete twice the job is 10 days.
Given:
4 men and 4 women can build a room in 5 days.
7 men and 2 women will take 4 days to complete the same piece of work.
To Find:
The number of days taken by 6 men and 1 woman to complete twice the job.
Solution:
We are required to find the number of days taken by 6 men and 1 woman to complete twice the job.
Let 'm' be the men and 'w' be the women
(4m+4w)×5 = (7m+2w)×4
20m+20w = 28m+8w
8m = 12w
2m = 3w
m/w = 3/2
m:w = 3:2
Total work = 20×3+20×2
Total work = 60+40
Total work = 100
For 6 men and 1 woman = 6m+1w
= 6×3+2
= 18+2
= 20
Time taken by 6 men and 1 woman to complete twice the job = 2×Totalwork/20 --------(1)
Substitute the value of total work in equation(1) we get
Time taken = 2×100/20
Time taken = 200/20
Time taken = 10 days
Therefore, The number of days taken by 6 men and 1 woman to complete twice the job is 10 days.
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