Question

4 men and 4 women can build a room in 5 days. 7 men and
2 women will take 4 days to
complete the same piece of work.
How many days will 6 men and 1
woman take to complete twice the
job?​

Answer 1

Step-by-step explanation:

(4 men +3 women)×6 days=(5 men +7 women)×4 days

24 men +18 women=20 men +28 women

4 men days =10 women days

1 men days =2.5 women days

Total work =24 men days +18 women days

=20 men days +28 women days

=78 women days

1 man +1 women =2.5 women +1 women =3.5  

women can do  

3.5

78

​  

=22(  

7

2

​  

) days

Answer 2

Answer:

The answer to the question is that 6 men and 1 woman can complete twice the work in 10 days.

Step-by-step explanation:

Given:

4 men and 4 women build a room in 5 days.

7 men and 2 women will complete the same room in 4 days.

To find :

How many will it take for 6 men and 1 woman to complete twice the job?

Solution :

let the work done by men and women in one day will be x and y respectively.

It is given that 4 men and 4 women can complete a room in five days

Then

$4x + 4y = \frac{1}{5} - - - (1)$

It is given that 7 men and 2 women can complete the same work in 4 days.

$7x + 2y = \frac{1}{4} - - - (2)$

on solving the equation 1 and 2 we get the answer as

$x = \frac{3}{100} and \: y = \frac{2}{100}$

one man's one-day work is

$\frac{3}{100}$

6 men's one-day work

$\frac{3}{100} \times 6 = \frac{18}{100}$

one women's one-day work

$\frac{2}{100}$

so, 6 men's and 1 women's 1 day's work is the addition of 6 men's one day work and one women's one day of work.

$\frac{18}{100} + \frac{2}{100} = \frac{20}{100}$

$\frac{1}{5}$

Hence, therefore 6 men and 1 woman can complete the work in 5 days.

6 men and 1 woman can complete twice the work in

$5 \times 2 = 10$

10 days.

Therefore, the final answer to the given question is 10 days.

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