4 men and 6 boys can finish a piece of work in 5 days while 3 men and 4 boys can finish it in 7 days find the time taken by one man alone or one boy alone
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Answered by
1
Answer:
One man can finish his work in 35 days and one boy can finish his work in 70 days
Step-by-step explanation:
No of days taken by 1 man =x days
No of days taken by 1 boy = y days
Work done by 1 men in 1 day = 1/x
Work done by 1 boy in 1 day =1/y
1st condition :
4/x +6/y =1/5
2nd condition ;
3/x+4/y =1/7
let 1 /x =a and 1/y =b
Multiply eq 1 by 3 and eq 2 by 4
12a +18b = 3/5
12a + 16b =4/7
Subtract
12a -12a + 18b -16b =3/5-4/7
2b=1/35
b =1/70
b = 70
put value
4/x +6/70 =1/5
1/x =1/4×(1/5-6/70)
a=35
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0
Answer:
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