Question

4 men and 6 women can finish a piece of work in 5 days while 3 men and 4 woman can finish it in 7 days. Then time taken by 1 man alone and 1 woman alone respectively is​

Answer 1

$\large\bf \underline\red{Question:- }$

4 men and 6 women can finish a piece of work in 5 days while 3 men and 4 woman can finish it in 7 days. Then time taken by 1 man alone and 1 woman alone respectively is

$\large\bf \underline\red{Answer:-}$

4M+3W=1/6 === ) ) 24M+18W=1.

-(1)

5M+7W=1/4 ===) ) ) 20M+28W=1-(2)

equating (1) &(2)

4M=10WV

I.e. M=(5/2)W

Put M value in (1)

W=1/78 and M=5/156

Now for 1M+1W=(5/1 56)+(1/69)=7/156

So 1 man and 1 woman can do job in (156/7) days