4 men and 6 women can finish a piece of work in 5 days while 3 men and 4 women can finish the same work in 7 days. then the time taken by 1 man alone and 1 woman alne to do the work is (A)man=35days and women =70days (B)men =25days women =50days (C) men =45days women =90days
(D)men =15 women =30
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Question:−
4 men and 6 women can finish a piece of work in 5 days while 3 men and 4 woman can finish it in 7 days. Then time taken by 1 man alone and 1 woman alone respectively is
Answer:−
4M+3W=1/6 === ) ) 24M+18W=1.
-(1)
5M+7W=1/4 ===) ) ) 20M+28W=1-(2)
equating (1) &(2)
4M=10WV
I.e. M=(5/2)W
Put M value in (1)
W=1/78 and M=5/156
Now for 1M+1W=(5/1 56)+(1/69)=7/156
So 1 man and 1 woman can do job in (156/7) days
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