4 men and 6 women complete a work in 8 days. 3 men and 7women complete it in 10 days . in how many days 10 women complete this work.
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We'll calculate it by equating the two statements for a day's work.
Let a man's one day's work be m and a woman's one day's work be w
As per the question, equations for work done per day:
I) 4m + 6w = 1/8
II) 3m + 7w = 1/10
Solving the two equations, we get: m =11/400, w = 1/400
So, a man's one day's work = 11/400 and a woman's one day's work = 1/400
Therefore 10 women's one day's work will be
10 x (1/400) = 1/40
That implies, 10 women will complete the work in 40 days.
Let a man's one day's work be m and a woman's one day's work be w
As per the question, equations for work done per day:
I) 4m + 6w = 1/8
II) 3m + 7w = 1/10
Solving the two equations, we get: m =11/400, w = 1/400
So, a man's one day's work = 11/400 and a woman's one day's work = 1/400
Therefore 10 women's one day's work will be
10 x (1/400) = 1/40
That implies, 10 women will complete the work in 40 days.
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