4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. 10 women working together will finish it in how many days ?
Answers
Answer:
Let 1 man's 1 day work = x and 1 woman's 1 days work = y.
Then 4x+6y= 1/8
and 3x+7y = 1/10
On solving we get y = 1/400
[means work done by a woman in 1 day] 10 women 1 day work = 10/400
= 1/40
10 women will finish the work in 40 days
Another method:-
According to question,
According to question,4m+6w=8 days....1
According to question,4m+6w=8 days....1or
According to question,4m+6w=8 days....1or32m+48w=1 days
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22w
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11w
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 1
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w∴(44w+6w)×8=10w×x
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w∴(44w+6w)×8=10w×x50w×8=10w×x
According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w∴(44w+6w)×8=10w×x50w×8=10w×xx=40 days