Math, asked by 919766620808, 2 days ago

4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. 10 women working together will finish it in how many days ?​

Answers

Answered by Souvikpal1234
1

Answer:

Let 1 man's 1 day work = x and 1 woman's 1 days work = y.

Then 4x+6y= 1/8

and 3x+7y = 1/10

On solving we get y = 1/400

[means work done by a woman in 1 day] 10 women 1 day work = 10/400

= 1/40

10 women will finish the work in 40 days

Another method:-

According to question,

According to question,4m+6w=8 days....1

According to question,4m+6w=8 days....1or

According to question,4m+6w=8 days....1or32m+48w=1 days

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22w

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11w

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 1

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w∴(44w+6w)×8=10w×x

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w∴(44w+6w)×8=10w×x50w×8=10w×x

According to question,4m+6w=8 days....1or32m+48w=1 days3m+7w=10 days....2or30m+70w=1 days∴32m+48w=30m+70w2m=22wm=11wfrom 14m=44w∴(44w+6w)×8=10w×x50w×8=10w×xx=40 days

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