4 men or 6 women can finish a work in 16 days. In how many days the
same work is completed by 2 men and 9 women?
(A) 12 days
(B) 10 days
(C) 9 days
(D) 8 days
Answers
Answer:
correct answer is 12 days mark me as brainliest
Answer:
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Step-by-step explanation:
Step-by-step explanation:
Given:
Let 1 man can do (\frac{1}{x})(
x
1
) of work per day and 1 woman can do (\frac{1}{y} )(
y
1
) of work per day .
We know that 4 men or 6 women can finish a work in 16 days,
4\times (\frac{1}{x} )\times 16 = 14×(
x
1
)×16=1
⇒ x=64
6\times (\frac{1}{y} ) \times 16 =16×(
y
1
)×16=1
⇒ y = 96
Now, the work completed by 2 by men and 9 women,
[ (2\times (\frac{1}{64} ))+(9\times(\frac{1}{96} ))]\times z = 1[(2×(
64
1
))+(9×(
96
1
))]×z=1
⇒ [ \frac{1}{32} +\frac{3}{32}]\times z = 1[
32
1
+
32
3
]×z=1
⇒ [\frac{1+3}{32}]\times z = 1[
32
1+3
]×z=1
⇒ [\frac{4}{32}]\times z = 1[
32
4
]×z=1
⇒ [\frac{1}{8}]\times z = 1[
8
1
]×z=1
⇒ z = 8
Therefore 2 men and 9 women can do the same piece of work in 8 days
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