Question

4 men throw a die each simultaneously. find the probability that at least 2 people get the same number

Answer 1

Given 4 men throw a die and 2 people get the same number.

1) The first die can give any of the 6 numbers.

2) The Second die can give any of the remaining 5 numbers.

3) The third die can give any of the remaining 4 numbers.

4) The fourth die can give any of the remaining 3 numbers.

So, the total possible outcomes will be = 6 * 5 * 4 * 3.


Probability of all getting different numbers = 6 * 5 * 4 * 3/6^4

                                                                        = 5/18.

Probability of 2 people get the same number = 1 - 5/18

                                                                             = 13/18.


Hope this helps!