4 mole of A and 8 mole of B is used. Find the no. of moles of the product.
2A + 3B ------------> A2B3
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The balanced chemical reaction is A+2B⟶C.
5 moles of A will react with 15×2=10 moles of B.
However, only 8 moles of B are present.
Thus, B is the limiting reagent.
Hence, 8 moles of B will give 28×1=4 moles of C.
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