Question

4 moles of A are mixed with 4 moles of B. At equilibrium for
the reaction A+B=C+D, 2 moles of C and D are formed. The
equilibrium constant for the reaction will be
1
(a)
(b)
=
(c) 1
(d) 4
:1:1...
notion of HLH​

Answer 1

Answer:

 A      +      B      ⇄      C      +       D

initial  -                4             4                0               0

at equilibrium    4-x          4-x             x=2           x=2

so final moles    2             2                  2              2

equilibrium constant

= [C][D] / [A][B] = [2][2] / [2][2] = 1