Question

4 moles of gas is enclosed in container is heated at constant presurre the temperature of the gas increases by 3degrees the work done by the gasis

Answer 1

Explanation:

For 1 mol of an ideal gas, ∆E = Cv*∆T

Heat transfer, Q = Cp* ∆T, because heat is transferred at constant pressure.

( Cp and Cv are the molar heat capacities at constant pressure and constant volume respectively for an ideal gas.)

From the 1st law of thermodynamics,

∆E = Q+W => W = ∆E - Q

W = Cv*∆T - Cp*∆T = (Cv-Cp)*∆T

For 1 mol of an ideal gas, Cp - Cv = R

W = - R*∆T

Putting, R = 8.314 J K^-1 mol^-1, ∆T = + 1 K

W = - 8.314 J mol^-1

Note the -ve sign, the work is done by the ideal gas in its expansion at constant pressure when temperature rises by 1K (or 1C).

Answer 2

Answer:

 The temperature ofthe gas increases by 3°C. The work … ... Four moles of a gas enclosed in a container is heated at ... Work done = 12R where R is the gas constant............................................

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