4 moles of nh4oh H and one mole of H2S o4 are mixed and diluted to 1 litre solution the pkb of nh4oh h is 4.8 the pH of solution is
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When 4 moles of NH4OH and one mole of H2SO4 are mixed and diluted to 1 litre solution and the pkb of ammonium hydroxide is given as 4.8 so to determine the kb go as follows;
kb= 10^-pkb
kb= 10^ -4.8
= 1.58 x 10^-5
therefore to determine degree of dissociation from kb, follow this;
kb = C∝²
where C is the concentration and ∝ is the degree of dissociation
1.58 x 10^-5 = 4∝²
∝ = 1.99 x 10^-3
then determine the equillibrium concentration of hydroxyl ions
[OH-] = C∝
[OH-] = 4 x (1.99 x 10^-3)
= 7.96 x 10^-3
so finally get the pOH= -log 7.96 x 10^-3
pOH= 2.1
Hence pH= 11.9.
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Explanation:
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