Question

(4) Multiply the given polynomials.
(i) 2x ; x2, 2x – 1
(ii) x-1 ; x3+ 2x2 +2
(iii) 2y +1; y2– 2y3 + 3y​

Answer 1

Answer:

i. (2x) x (x2 – 2x – 1) = 2x3 – 4x2 – 2x ii. (x5 – 1) × (x3 + 2x2 + 2) = x5(x3 + 2x2 + 2) -1(x3 + 2x2 + 2) = x8 + 2x7 + 2x5 – x3 – 2x2 – 2 iii. (2y + 1) × (y2 – 2y3 + 3y) = 2y(y2 – 2y3 + 3y) + 1(y2 – 2y3 + 3y) = 2y3 – 4y4 + 6y2 + y2 – 2y3 + 3y = -4y4 + 2y3 – 2y3 + 6y2 + y2 + 3y = -4y4 + 7y2 + 3y

Step-by-step explanation:

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