Math, asked by mrmanishkumarjee, 11 months ago

4^n+2^n=2 find the value of n

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Answered by bedabrata85

$<body bgcolor="teal">2^{2n}+2^{n}=2\\Let \:2^{n} \:be \:x\\2 ^{n} + 2 ^{n} \times 2^{n} = 2 \\ = > {2}^{n} (1 + {2}^{n} ) = 2 \\ = > n = 1 \: or \: {2}^{n} = {2}^{0} \\ = > n = 1 \: or \: n = 0$

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4^n+2^n=2 find the value of n​

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4^n+2^n=2 find the value of n