Question

4. NA 49) The velocity-time graph for a particle moving in a given direction is as shown in the figure : (a) From the graph, find the acceleration of the particle. (b) What is the force acting on the particle if its mass is 600 g?

please easy way m answer dena​

Answer 1

Answer:

Acceleration = 2 ms^(-2)

F = 1.2 N

Explanation:

The slope of velocity time graph is acceleration . to find slope of curve which is straight line here take any two points on v-t graph

at t = 0 , v = 0 ; Point ( 0 , 0 )

at t = 3 , v = 6 ; Point ( 3 , 6 )

So slope

$a = \frac{v_2 - v_1}{t_2 - t_1} = \frac{6 - 0}{3 - 0} = 2 \: m {s}^{ - 2}$

Now force = mass × acceleration

$f = ma = \frac{600}{1000} \times 2 = \frac{9}{5} = 1.2 \: n$

Answer 2

Answer: acceleration= 2m/s-2

Force= 1.2N

Explanation: slope of velocity-time graph gives acceleration...then force is equal to the product of mass and acceleration.