Question

4. Number of carbon atoms present in 22g Co2 is
(1) 6.02 * 1023
(2) 3.01 * 1023
(3) 3.01 * 10-23
(4) 6.02 x 10-23​

Answer 1

Answer:

(2) 3.01 *10^23

Explanation:

No. of  atoms= no. of moles * 6.023*10^23

                      = 22/44*6.023*10^23

                      =3.01 *10^23

Answer 2

Hi there,

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Given

• CO2 sample mass = 22 gm

• CO2 molar mass = 12+16×2 =44 gmm

• No. C atoms in one molecule = 1 atom

• Avogadros no = 6.02×10^23

☆ First calculate no. Of moles by divide sample mass over molar mass

◇ n = Ms ÷ M.wt = 22 ÷ 44 = 0.5 mol

☆ Find the no. Of molecules by multiply moles time avogadros no

N = mols × NA = 0.5 × 6.02×10^23

◇ N = 3.01×10^23

☆ Each molecule contain 1 C atom

So, total carbon atoms =

◇ 1 × 3.01×10^23 = 3.01×10^23 atom

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