Question

4. Obtain all zeros of f(x) = x3 + 13x2 + 32x + 20, if one of its zeros is – 2.
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Answer 1

Answer:

the zeros of the given polynomials are -2, -1, and -10.

Step-by-step explanation:

Since −2 is one zero of f(x)

Therefore, we know that, if x = a is a zero of a polynomial, then x - a is a factor of f(x) = x + 2 is a factor of f(x)

Now, we divide f(x) = x3 + 13x2 + 32x + 20 by g(x) = (x + 2) to find the others zeros of f(x).

By using that division algorithm we have,

f(x) = g(x) x q(x) + r(x)

x3 + 13x2 + 32x + 20 = (x + 2)(x2 + 11x +10) + 0

x3 + 13x2 + 32x + 20 = (x + 2)(x2 + 10x + 1x +10)

x3 + 13x2 + 32x + 20 = (x + 2)[x(x + 10) + 1(x + 10)]

x3 + 13x2 + 32x + 20 = (x + 2)(x + 1)(x + 10)

Hence, the zeros of the given polynomials are -2, -1, and -10.

Answer 2

Answer:

let x be 2.,

f(x) = x^3 + 13x^2 + 32x + 20

f(2) = 2^3 + 13(2)^2 + 32(2) + 20

f(2) = 8 + 26^2 + 64 + 20

f(2) = 8 + 676 + 64 + 20

f(2) = 768

(f = 768/2

f= 384)

Step-by-step explanation:

the bracket part is not required in this formula but if they say find value if f if x is equal to any value then u have to write the bracket part....

hope u can understand my solving method

thank u