Question

4. Of three consecutive numbers twice the greatest and 4 times the smallest one are
together equal to 70. Find the numbers.​

Answer 1

Answer:

9.29, 10.29, 11.29

Step-by-step explanation:

let consecutive numbers are x-1, x, x+1

4(x-1) + x + 2(x+1) = 70

7x - 2 =70

× = 72/7 = 10.29

x-1 = 9.29

x+1 = 11.29