Question

4. Of three consecutive numbers twice the greatest and 4 times the smallest one
are together equal to 70. Find the numbers.
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Answer 1

Answer:

Let n = the least of the 3 consecutive numbers.

n+1 = the middle number

n+2 = the greatest number

Now build an equation:

Twice the greatest: 2•(n+2)

Added to: +

Three times the least: 3•n

Amount to 34: = 34

Put it all together and solve for n.

2(n+2) + 3n = 34

2n + 4 + 3n = 34

5n = 30

n = 6

n is the least of the 3 consecutive numbers, so…

The 3 consecutive numbers are 6, 7, and 8.

Step-by-step explanation:

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