Physics, asked by Anagha, 1 year ago

4 ohm 6 ohm
|-----/\/\/\/\/\---------------/\/\/\/\/\/\--------|
|---------------|    |-----------------|
| |------/\/\/\/\/\---------------/\/\/\/\/\/\-------| |
| 8 ohm 12 ohm |
| |
|-------------------| |---------------------------------------------------------------| 6 V    A 12 V battery is connected to the arrangement of resistances given above.
Calculate--
1) the resultant resistance of the circuit.
2) the current flowing in the circuit.

Answers

Answered by Anonymous

   4 ohm 6 ohm
|-----/\/\/\/\/\---------------/\/\/\/\/\/\--------|
|---------------|    |-----------------|
| |------/\/\/\/\/\---------------/\/\/\/\/\/\-------| |
| 8 ohm 12 ohm |
| |
|-------------------| |---------------------------------------------------------------| 12 V    A 12 V battery is connected to the arrangement of resistances given above.
Calculate--
1) the resultant resistance of the circuit.
2) the current flowing in the circuit.

Solution :
   See in the above circuit ,
   4ohm and 6ohm resistances are in series ,
   therefore their equivalent resistance = 10 ohm
   Similarly ,
   8 ohm and 12 ohm resistances are in series,
therefore there equivalent resistance = 20ohm
   hence our Circuit modifies as follows
        10 ohm
|-----/\/\/\/\/\/\/\/\/\/\/\--------|
|---------------|       |-----------------|
| |------/\/\/\/\//\/\/\/\/\/\-------| |
|     20 ohm        |
|    |
|-------------------| |----------------------------------------------|       12 V

Now 10ohm and 20 ohm resistances are in Parallel , hence their equivalent resistance
   = product of resistances/sum of resistances
   = 10 *20 /10+20
   = 200 /30
   = 20/3 ohm
hence the resultant resistance of the circuit is (20/3)ohm

b )
   We know that ,
   V=IR
   or I = V/R
   = 12 / 20 /3
   = 12*3/20
   = 36/20
   = 18/10
   = 1.8 Ampere
Hence Current = 1.8 Ampere.

Hope this helps You!!

Answered by ankitkumar0102

   4 ohm 6 ohm
   A |-----/\/\/\/\/\---------------/\/\/\/\/\/\--------| B
|---------------|    |-----------------|
|    D |------/\/\/\/\/\---------------/\/\/\/\/\/\-------| C    |
| 8 ohm 12 ohm |
| |
|-------------------| |---------------------------------------------------------------|    6 V
In loop ABCD,
A to B is in series and D to C is also in series, but AB and CD is in parallel arrangement.

Therefore, Resultant resistance in branch AB = 4 ohms + 6 ohms = 10 Ohms
Resultant resistance in branch CD = 12 ohms + 8 ohms = 20 Ohms

So the resultant resistance of the circuit = 1/10 + 1/20 = 3/20 = 0.3 Ohm

According to Ohm's Law:-
V = I * R
6V = I * 0.3
I = 20 Amperes

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