Question

4. One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?​

Answer 1

Answer:

The original number is : 62 or 26

Given:

➡One of the two digits of a two digit number is three times the other digit.

➡If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

To Find:

The original number

Solution:

We are given,

➡One of the two digits of a two digit number is three times the other digit.

➡If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

Let the digit in units place be m.

Then, digit in ten's place =3m. [ given ]

So, original number = 10( 3m ) + m = 31m

On interchanging the digits, new number =

➞10m + 3m = 13m

◉According to the given condition,

➞31m + 13m = 88

➞44m = 88

➞m = 2

So, the original number is 31m or 31 ×2 =62.

◉On the other hand, if we consider the digit in ten's place as m , then the digit in unit's place will be 3m.

So, the resulting number we get is 26.

Here, both answers are correct, as 26+62 = 88.

Hence the original number is 26 or 62.