Question

4. One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?​

Answer 1

Answer:

Let tens place be x and one’s be y.

So the number is 10x + y.

x = 3 times y. => x - 3y = 0 -> (1)

The interchanged number is 10y + x.

So, on adding, we get 11x + 11y = 88

Or x + y = 8 -> (2) (on dividing whole by 11).

Now we have to subtract. So we get 4y = 8. Therefore y = 2, and x = 8-2 =6 (from 1st eq.)

Hence the answer is 62 and 26.

Hope the answer helped you. Pls mark as brainliest! :)

Answer 2

Answer:

The original number will be 26 or 62

Step-by-step explanation:

Let one digit be x

So, the other digit is 3x

The number formed will be 10x + 3x = 13x

After interchanging the digits,

(10×3x) + x  = 30x + x  = 31x.

After adding both numbers,

13x + 31x = 88

44x = 88

x = 2.

So,

The number formed is (10×2) + (3×2) = 20 + 6 = 26

Or it can also be 62