Question

4. One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?
​

Answer 1

Step-by-step explanation:

Let one digit be x.

So, the other digit is 3x.

The number formed will be 10×x + 3x.

=10x+3x

=13x.

After interchanging the digits,

10×3x + x

=30x + x

=31x.

After adding both numbers,

13x + 31x = 88

44x = 88

X = 2.

So, the number formed is 10×2 +3×2 = 20+6=26.

Or it can also be 62.

Answer 2

pls mark as brainlist answer

Let the digit in units place be x.

Then, digit in ten's place =3x

So, original number =10(3x)+x=31x

On interchanging the digits, new number =10x+3x=13x

According to the given condition,

31x+13x=88

⇒44x=88

⇒x=2

So, the original number is 31x or 31×2=62.

On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.

So, the resulting number we get is 26.

Here, both answers are correct, as 26+62=88.