Question

4. One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?
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Answer 1

✽ Question ✽

One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

✽ Given ✽

One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

✽ To find ✽

The original number.

✽ Solution ✽

Let the ones digit be x.

So, tens digit = 3x.

According to condition,

{10(3x)+x} + {10x+3x} = 88

→ (30x+x) + (10x+3x) = 88

→ 31x + 13x = 88

→ 44x = 88

→ x = 88/44

→ x = 2

✽ Hence ✽

x = 2

So, ones digit = x = 2

And tens digit = 3x = (3×2) = 6

So, the original digit

= 10(6) + 2

= 60 + 2

= 62

✽ Therefore ✽

The original digit is 62.

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✽ Verification ✽

{10(3x)+x} + {10x+3x} = 88

→ 62 + 26 = 88

→ 88 = 88

So, L.H.S = R.H.S.

Hence, verified.

◎ Hope this helps you. ◎