Question

4. One side of a rectangular field is 15 m and one of its diagonal is 17 m. Find the area of a field.​



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Answer 1

Area of the field = 120 m².

Step-by-step explanation:

One side of the rectangular field = 15 m

One of its diagonal = 17 m

Now find the other side of the rectangular field by using ' Pythagoras Theorem '.

From the attachment :

AD= length = 15 m

AC = Diagonal = 17 m

DC² + AD² = AC²

→ DC² + 15² = 17²

→ DC² = 17² - 15²

→ DC² = 64

→ DC = √64

→ DC = 8

Therefore, breadth of the rectangular field is 8 m.

We know that,

${\boxed{\large{\sf{Area\:of\: rectangle=length\times\: breadth}}}}$

→ Area of the field = (15×8) m²

→ Area of the field = 120 m²

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More info:

• Perimeter of rectangle = 2(length× breadth)
• Diagonal of rectangle = √(length ²+breadth ²)
• Area of square = side²
• Perimeter of square = 4× side

Answer 2

Question:-

• One side of a rectangular field is 15 m and one of its diagonal is 17 m. Find the area of a field.

Answer:-

• Let the other side be x
• Now, (17)^2 = (15)^2 +(x)^2
• 289 = 225+x^2
• x^2 = 289-225 = 64
• x = 8
• Area = 15*8 = 120 Ans.

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