Question

4/(p-3) +6/(9-4)=5 5/(p-3)-3/(9-4)=1 by elimination method​

Answer 1

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$\frac{4}{p - 3} + \frac{6}{9 - 4} = 5$

$\frac{5}{p - 3} - \frac{3}{9 - 4} = 1$

WE WOULD ADD THESE EQUATIONS TOGETHER:

$\frac{4}{p - 3} + \frac{5}{p - 3} + \frac{6}{5} - \frac{3}{5} = 6$

$\frac{9}{p - 3} + \frac{3}{5} = 6$

$\frac{9}{p - 3} = 6 - \frac{3}{5}$

$\frac{9}{p - 3} = \frac{27}{5}$

$\frac{1}{p - 3} = \frac{27}{5 \times 9}$

$\frac{1}{p - 3} = \frac{27}{45}$

$\frac{1}{p - 3} = \frac{3}{5}$

$\frac{1}{p - 3} \times \frac{5}{3} = 1$

$1 \times \frac{5}{3} = p - 3$

$5 = 3(p - 3)$

$5 = 3p - 9$

$5 + 9 = 3p$

$3p = 14$

$p = \frac{14}{3}$