Question

4 P(Y) = y3 + 2y ²-3 then find
- the value p(l) and p (0)​

Answer 1

Answer:

hey frnd here is your answer

Step-by-step explanation:

P(y)= y³+2y²-3

we want P(1) and P(0).

P(1)= (1)³+2(1)²-3= 1+2-3= 0.

so P(1)=0.

P(0)= (0)³+2(0)²-3= -3.

so P(0)= -3.

so your final answer is-

P(1)= 0 and P(0)= -3.

plzz mark as brainlist.. if you get the right answer

Answer 2

$\huge{\underline{\tt{QUESTION:-}}}$

P(Y) = y3 + 2y ²-3 then find - the value p(l) and p (0)​ ?

$\huge{\underline{\tt{ANSWER:-}}}$

See the attachment !