Question

4 particles P, Q, R and S start from point A on a circle of radius 10m to reach the point B . Find the displacement vectors for each of these along with magnitude and calculate the distance covered by them.

Answer 1

Answer:

10.m pqr s, a, p

distance relationship with you and S, A, P

Answer 2

Answer:

•D(P): 15π m

•D(Q): 20m

•D(R): 5π m

•D(S): 14m

• S(Displacement): (10i-10j):(10√2m)

Here Is Your Solution-

(i) Case-(P);

P covers (3/4)th of the circle starting from A

(intial point) to B (final point)

So, Dist. P= (3/4)(2πr)

Dist. P=(3/4)(2)(π)(10)

Dist. P= 15π m

(ii) Case-(Q);

Q covers r(OA) and r(OB) to reach B.

So, Dist. Q=(2)(r)

Dist. Q=2(10)

Dist. Q= 20m

(iii) Case-(R);

R covers (1/4)th circumference of circle from A(intial point) to B(final point)

So, Dist. R=(1/4)(2πr)

Dist. R=(1/4)(2)(π)(10)

Dist. R= 5π cm

(iv) Case-(S);

S Directly covers the shortest path b/w A and B

In ∆AOB;

If OA is considered as 10i m and OB is consider as -10j m on a Cartesian plane, then

Dist. AB= 10i-10j

Dist. (AB)= √(OA)²+(OB)²

Dist. (AB)=√(10)²+(10)²

Dist. (AB)=√200= 10√2m

Since; Path covered by S is shortest path b/w A and B. Therefore 10√2m is displacement for all the other particles.

Hope It Helps!