Question

4 points
10. Three particles are executing S.H.M. respectively according to the
equations:
X1 = 6 sin(10nt + 1/3)
X2 = 6 sin(8nt + 7/4)
X3 = 5 cos (87t + a
The phase difference between the first and third particle at t= 0,5 second is:
(a) 71/12
O (b) 131/12
O (c) 251/12
O (d) 11/12

Answer 1

Answer:

C 251 / 12

Explanation:

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