Physics, asked by shreyamanapure, 9 months ago

4. Positive charges of 9 nC and 4 nC are placed at the points A and C respectively of a right angled
Triangle ABC in which <B -90°. AB = 3 cm and BC =2cm. Find the electric intensity at B.ans is...... (12.73
x 10' N/C making a=45° with E, and E.)

Answers

Answered by Anonymous
0

Answer:

The force exerted by one charge q on another charge Q is given by Coulomb's law: r is the distance between the charges. Remember that force is a vector, so when more than one charge exerts a force on another charge, the net force on that charge is the vector sum of the individual forces.

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