Question

4 power 4 into 16 power minus 2 into 4 power 0

Answer 1

Answer:

1

Step-by-step explanation:

${4}^{4} \times {16}^{ - 2} \times {4}^{0} \\ \\ {4}^{4} \times { {4}^{2} }^{ - 2} \times {4}^{0} \\ \\ {4}^{4 - 4 +0} \\ \\ = {4}^{0} = 1$

Answer 2

Given:

An expression in exponential form$4^4 * 16^{-2} * 4^{0}$,

To Find:

The value of the given expression.

Solution:

The given problem can be solved using the concepts of exponents.

1. The given expression is$4^4 * 16^{-2} * 4^{0}$,

2. The formulae that we use to solve the given expression are:

• $x^0$ = 1 for all the cases for any values of x (excluding 0).
• $x^{a^{b} }$ =$x^{ab}$,
• $x^{-a}= \frac{1}{x^{a} }$.

3. Using the formulae mentioned above the given expression can be solved,

=>$4^4 * 16^{-2} * 4^{0}$,

=>$4^4 * 16^{-2} * 1$,

=>$4^4 * 4^{2^{(-2)} }$,

=>$4^4 * 4^{-4}$,

=> $\frac{4^4}{4^4}$ = 1.

Therefore, the value of the expression 4^4 x 16^-2 x 4^0 is 1.