Question

4) Power of lens is +5D . An object is placed at a distance of 40cm from the lens
where is the image formed what is the nature of the image and position ?please guys urgent I will follow you

Answer 1

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

Power of lens = +5D

Distance of object = 40cm

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find position and nature of the image.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

First of all we need to find focal length of lens afrer that, we will calculate position of image by using lens formula.

❂ Focal length of lens :

$:\implies\tt\:P=\dfrac{1}{f}$

$:\implies\tt\:5=\dfrac{1}{f}$

$:\implies\bf\:f=0.2\:m=20\:cm$

❂ Position of image :

$:\implies\tt\:\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

$:\implies\tt\:\dfrac{1}{v}-\dfrac{1}{(-40)}=\dfrac{1}{20}$

$:\implies\tt\:\dfrac{1}{v}=\dfrac{1}{20}-\dfrac{1}{40}$

$:\implies\tt\:\dfrac{1}{v}=\dfrac{2-1}{40}$

$:\implies\boxed{\bf{\gray{v=40\:cm}}}$

❂ Nature of image :

• Real
• Inverted

Answer 2

Nature of image :

Real

inverted