Question

4.Product of two numbers is 6300 and their HCF is 15 find their LCM
a)450
b)320
C)430
d)420​

Answer 1

Answer:

Let the two numbers be x and y respectively.

It is given that the product of the two numbers is 6300, therefore,

      

xy=6300

Also 15 is their HCF, thus both numbers must be divisible by 15.

So, let x=15a and y=15b, then  

15a×15b=6300⇒225ab=6300⇒ab=2256300⇒ab=28

           

Therefore, required possible pair of values of x and y which are prime to each other are (1,28) and (4,7).

Thus, the required numbers are (15,420) and (60,105).

Hence, the number of possible pairs is 2.

Answer 2

Step-by-step explanation:

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