4. Prove that 2a0 = w2 - w^2o
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(1+ω 2 +2ω) 3n
−(1+ω+2ω 2 ) 3n
∵ω 2 +ω+1=0
⇒ω 2 +2ω+1=ω
1+ω+2ω 2 =ω 2
⇒(ω)
3n −(ω 2 )
3n =(ω
3 ) n −(ω 3 ) 2n =1−1=0.
here's the answer......
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