Question

4. Prove that a line drawn through the mid-point of one side of a triangle parallel to
side bisects the third side (Using basic proportionality theorem).


INTRIANGLE ABC D IS THE MID POINT OF AC ,E IS THE MID POINT OF AC​

Answer 1

Answer:

Detailed solution is given in photo

Answer 2

Given,In triangle ABC, D is the midpoint of AB such that AD=DB.

A line parallel to BC intersects AC at E as shown in above figure such that DE||BC.

To prove, E is the midpoint of AC.

Since, D is the midpoint of AB

So,AD=DB

⇒ AD/DB=1.....................(i)

In triangle ABC,DE||BC,

By using basic proportionality theorem,

Therefore, AD/DB=AE/EC

From equation 1,we can write,

⇒ 1=AE/EC

So,AE=EC

Hence, proved,E is the midpoint of AC.