) (4) Prove that any non-isosceles trapezium
is not cyclic.
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3
Answer:
Step-by-step explanation:
To prove that any given quadrilateral is cyclic, we need to prove that its opposite angles are supplementary (i.e. they add up to 180˚). We need to prove that ∠BAD + ∠BCD = 180 and ∠ADC + ∠ABC = 180˚. ... Thus, ΔADF ≅ ΔBCE by RHS ( Right angle - Hypotenuse - Side ) congruency.
Answered by
1
Answer: To prove that any given quadrilateral is cyclic, we need to prove that its opposite angles are supplementary (i.e. they add up to 180˚). We need to prove that ∠BAD + ∠BCD = 180 and ∠ADC + ∠ABC = 180˚. ... Thus, ΔADF ≅ ΔBCE by RHS ( Right angle - Hypotenuse - Side ) congruency.
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