Math, asked by savarnikaveeramally, 6 months ago

4 .Prove that tan 50° -tan 40° = 2 tan 10°

Answers

Answered by dazzy09

6

tan (A-B) = (tan A - tan B) / (1 + tan A tan B)

A = 50 . B = 40 deg

tan 50 = cot (90-50) = 1/tan 40

LHS = tan(50-40) (1+tan 50*tan40*)

= tan10 (1+1)

= 2 tan 10

Answered by AashutoshKrMondal

4

Answer:

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