Math, asked by elangovan66, 8 months ago

4. Prove that the pair of linear equations
2x - 3y = 5 and 6x + 4y - 10 = 0 have
one solution only.​

Answers

Answered by rohitrs0908
3

Answer:

Step-by-step explanation:

2x - 3y = 5 -------------(1)

6x + 4y - 10 = 0

6x + 4y = 10 -----------------(2)

(1)*3

6x-9y=15 -----------------(4)

(2)-(4)

13y= -5

y = -5/13

Substitute y=-5/13 in (1)

2x-3(-5/13)=5

2x+15/13=5

2x=50/13

x=25/13

Answered by Vijayashree22
2

Answer:

Given-a1=2 ,b1=-3 ,c1=-5 a2=6 ,b2=4, c2=-10

step by step instructions-

Now,

a1/a2=2/6=1/3

b1/b2=-3/4

c1/c2=-5/-10=1/2

That Implies,

a1\a2 is not equal to b1\b2 But b1\b2=c1\c2

SO,the given equation has unique solution

Therefore, the given equation has one solution

THANK YOU.Hope it helps

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