4. Prove that the pair of linear equations
2x - 3y = 5 and 6x + 4y - 10 = 0 have
one solution only.
Answers
Answered by
3
Answer:
Step-by-step explanation:
2x - 3y = 5 -------------(1)
6x + 4y - 10 = 0
6x + 4y = 10 -----------------(2)
(1)*3
6x-9y=15 -----------------(4)
(2)-(4)
13y= -5
y = -5/13
Substitute y=-5/13 in (1)
2x-3(-5/13)=5
2x+15/13=5
2x=50/13
x=25/13
Answered by
2
Answer:
Given-a1=2 ,b1=-3 ,c1=-5 a2=6 ,b2=4, c2=-10
step by step instructions-
Now,
a1/a2=2/6=1/3
b1/b2=-3/4
c1/c2=-5/-10=1/2
That Implies,
a1\a2 is not equal to b1\b2 But b1\b2=c1\c2
SO,the given equation has unique solution
Therefore, the given equation has one solution
THANK YOU.Hope it helps
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