Question

4. Prove that the points (3,-2),(4.0), (6,-3) and (5,-5) are the vertices of a parallelogram​

Answer 1

Answer:

sahid ah verticles of a parallelogram han

Answer 2

Let the vertices of a parallelogram be A(−3,2), B(4,0), C(6,−3) and D(5,−5)

So by distance formula we have,

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

AB=

(4+3)

2

+(0+2)

2

=

5

CD=

(5−6)

2

+(−5+3)

2

=

5

BC=

(6−4)

2

+(−3)

2

=

13

AD=

(5−3)

2

+(−5+2)

2

=

13

Opposite site of a parallelogram are equal.

Therefore AB=CD=

5

and BC=AD=

13

ABCD is a parallelogram (PROVED)