4) Prove that the sum of measure of all angles in a triangle is 180°.
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Answer:
all sides of a triangle are equal so angle formed between them will also be equal
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Given :
A triangle ABC.
To prove :
∠A+∠B+∠C=180°
⟹∠1+∠2+∠3=180°
Construction :
Through A, draw a line l parallel to BC.
Proof :
Since l∥BC. Therefore,
∠2=∠4 .......eq(i)
And, ∠3=∠5......eq(ii)
adding eq(i)and(ii)
Therefore, ∠2+∠3=∠4+∠5
∠1+∠2+∠3=∠1+∠4+∠5 [adding∠1bothSide]
∠1+∠2+∠3=180 °
Thus, the sum of three angles of a triangle is 180° .
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