4. Prove the following:
3√9×3√1728=3√9×1789
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2560 2560 can be expressed as the product of prime factors in the following manner: ... Answer: 3√729. By prime factorisation: 729 = 3×3×3×3×3×3 = (3×3×3)×(3×3×3) ∴ 3√729 = (3×3)= 9
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This is the solution.......
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