Question

(4)
Q.3 )Rohit borrowed Rs. 60,000 from a bank at 9% p.a. for 2 years. He
lent this sum of money to Mohit at 10% p.a. for 2 years. How much did
Rohit earn from this transaction ?
Solution:
Interest paid by Rohit Interest received by Rohit
Principal -
Principal -
I
Rate -
9% p.a.
Rate
Time -
Time - 2 years
Interest paid by Rohit
Interest received by Rohit
S.I. = PXOXO
100
S. I. = 60,000 x
100
S.I.= DX RX
100
S. I. = x 10 x
100
S. l. =
S. 1. =
Interest earned by Rohit =
Interest paid by Rohit
Interest earned by Rohit = Rs. 12,000
Interest earned by Rohit =
Hence, through this transaction Rohit earnedस्टेप बाय स्टेप ​

Answer 1

Answer:

Answer

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Given, Principal amount lent by Rohit = Rs 60000

R = 10 %

T = 2 years

Interest =

100

P×R×T

=

100

60000×10×2

= Rs 12000

Principal amount borrowed by Rohit = Rs 60000

R = 9 %

T = 2 years

Interest =

100

P×R×T

=

100

60000×9×2

= Rs 10800

Amount gained by Rohit = 12000−10800=1200