4π(r+dr)^2 - 4πr^2
prove that 8πrdr
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Surface tension derivation?
ya
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Hola User_______________
Here is Your Answer..!!!
_________________________
⭐Actually welcome to the concept of the SURFACE TENSION. . pressure expansion in a Bubble
⭐Since there is change in the surface area ...
⭐the Surface Energy is given by
⭐dw = T.dA
Here is Your Answer..!!!
_________________________
⭐Actually welcome to the concept of the SURFACE TENSION. . pressure expansion in a Bubble
⭐Since there is change in the surface area ...
⭐the Surface Energy is given by
⭐dw = T.dA
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4π(r+dr)² - 4πr²
= 4πr²(1+d)² - 4πr²
= 4πr²[ (1+d)² - 1]
=4πr²[1+d²+2d -1]
=4πr²[d²+2d]
=4πr²d[d+2]
= 4πr²d[2r+2]
=8πr²d[r+1]
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