Question

4. Radius of a circle with centre O is 25 cm. Find the distance of a chord from the centre if length of the chord is 48 cm. 

7 cm

14 cm

8 cm​

Answer 1

Answer:

Perpendicular drawn from the centre of the circle to the chord bisects the chord.

So, PD = ½ CD = 48÷2 = 24cm

In ∆OPD,

We apply the pythagoras theorem,

OP² + PD² = OD²

→ OP² +24² = 25²

OP² = 25²-24² = 625-576 = 49

→ OP² = 49

⇒ OP = 7 CM

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