Physics, asked by siddhantgupta928, 18 days ago

4. Raj connected 2 lamps with a battery as shown below. The current flowing through the circuit is of 6.0 A. B o X + A

(a) What does the circuit diagram tell us about the lamps?

(b) What will be the current at point B?​

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Answered by vishakha756
0

Explanation:

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Answered by Anonymous
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V=6V

R1=2ohms

R2=3ohms

(a) Resistors are connected in parallel.

(b) p.d. across each resistor is same and is equal to 6V.

(c) 2 ohms resistance have bigger share of current because of its lower resistance.

(d) Effective resistance = R

1/R=1/2+1/3

1/R=5/6

R=1.2ohms

(e) Current flowing through battery , 

I=RV=1.26=5amps 

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