4) Ravi opens a recurring deposit account of Rs.800 per month at 7% p.a. If he receives Rs.20600 at the time of maturity, find the time in years for which the account was held.
please give the correct answer, don't give unnecessary answer.
Class 10 ICSE Banking.
Answers
Answer :
Here, P= money deposited per month = Rs. 800
n= Time for which the money is deposited =121 years =18 months.
Let the rate of interest be r% per annum, then
Interest =P×2×12n(n+1)×100r
=800×2×1218×19×100r
= Rs. 114r
Total money deposited =18×800= Rs. 14,400
Since money deposited + interest = Maturity value
⇒14,400+114r=15,084
⇒114r=15,084−14,400
⇒114r=684
⇒r=114684=6
Hence, rate of interest =6% p.a.
Ravi has an Recurring Deposit Account of Rs 800 per month.
The rate of interest is 7 % p.a.
He get Rs 20600 on the time of maturity.
Time in years.
Amount on a certain sum of money of Rs P invested per month at the rate of r % per annum for n months is
Given that,
Ravi has an Recurring Deposit Account of Rs 800 per month.
The rate of interest is 7 % p.a.
He get Rs 20600 at the time of maturity.
Let assume that the RD is deposited for n months.
So, on substituting the values in the formula
We have,
Sum deposited, P = Rs 800
Rate of interest, r = 7 % per annum
Maturity Value = Rs 20600
Its a quadratic equation in 'n',
So, by using splitting of middle terms, we have
So,
- Time = 2 years.