4 registrant of 5 Om are connected in a Circuit in a parallel order. Find the equivalent resistance of the circuit
Answers
Answered by
0
Since 1Ω and 106 Ω are connected in parallel
then the equivalent resistance R will be
R
1
=
1
1
+
10
6
1
R=
10
6
+1
10
6
~
10
6
10
6
R=1Ω
Equivalent resistance is 1Ω
(b) 1Ω and 103Ω and 160Ω are in parallel
R
1
=
1
1
+
10
3
1
+
10
6
1
R
1
=
10
6
10
6
+10
3
+1
R
1
=
1000000
1001001
R=0.999Ω
Therefore, equivalent resistance =0.999Ω
Similar questions